dwords
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例句
No. The variants are not strongly typed and the execution options are not enumerations, but generic DWORDs.
顯然不是,variants不是強類型的,執行參數也沒有定義為枚舉類型而是整數。
In keeping with the MASM32 practice of "loose" type checking, function parameters are just defined as DWORDs.
為了保持MASM32的“松散”類型檢查的原則,函數參數只是被定義為DWORD。